**SOLUTION I do not know how to find the x-intercept and**

To find the x-intercepts we use such methods as setting the equation equal to zero and factor, completing the square or using the square root method. For the y-intercept we set x=0 and solve for f(x). The vertex and axis of symmetry can be found by converting the equation from standard form to vertex form by completing the square.... I received a problem in my math class the other day that left me stumped. The problem went something like this. Mr. Lots-O-Cash would like to order a parabola …

**SOLUTION I do not know how to find the x-intercept and**

I received a problem in my math class the other day that left me stumped. The problem went something like this. Mr. Lots-O-Cash would like to order a parabola …... It is the constant value, the only term without any x’s. To see why, if you plug [math]x=0[/math] (the equation of the y-axis) into the equation, all the terms with x’s equate to 0, leaving y = c.

**How do you find the vertex and the intercepts for y = x^2**

I received a problem in my math class the other day that left me stumped. The problem went something like this. Mr. Lots-O-Cash would like to order a parabola … how to fix computer lag windows 7 24/05/2011 · Best Answer: Hint: Using the x-intercepts and y = ax² + bx + c, find the quadratic formula. Remember that x-intercepts are the roots of the function, so... Remember that x-intercepts are the roots of the function, so...

**Finding the Vertex mathed.page**

To find the x-intercepts we use such methods as setting the equation equal to zero and factor, completing the square or using the square root method. For the y-intercept we set x=0 and solve for f(x). The vertex and axis of symmetry can be found by converting the equation from standard form to vertex form by completing the square. how to find lost iphone without app 0=x^2+8x+8 ___ is not factorable ___ use the quadratic formula to find the roots (x-intercepts) the vertex is on the axis of symmetry the equation for the axis of symmetry is x=-b/(2a)

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### Finding the Vertex mathed.page

- Finding the Vertex mathed.page
- Finding the Vertex mathed.page
- Finding the Vertex mathed.page
- How To Find The Vertex And X Intercepts Of A Quadratic

## How To Find Vertex Without X Intercepts

Vertex is at (3, -1) ; y-intercept is at (0,8) and x-intercepts are at (2,0) and (4,0) We know the equation of parabola in vertex form isy=a(x-h)^2+k where vertex is at (h,k).Here y=x^2-6x+8= (x-3)^2-9+8=(x-3)^2-1 :.Vertex is at (3, -1) we find y-intercept by putting x=0 in the equation. So y=0-0+8=8 and x-intercept by putting y=0 in the equation.

- Vertex is at (3, -1) ; y-intercept is at (0,8) and x-intercepts are at (2,0) and (4,0) We know the equation of parabola in vertex form isy=a(x-h)^2+k where vertex is at (h,k).Here y=x^2-6x+8= (x-3)^2-9+8=(x-3)^2-1 :.Vertex is at (3, -1) we find y-intercept by putting x=0 in the equation. So y=0-0+8=8 and x-intercept by putting y=0 in the equation.
- Vertex is at (3, -1) ; y-intercept is at (0,8) and x-intercepts are at (2,0) and (4,0) We know the equation of parabola in vertex form isy=a(x-h)^2+k where vertex is at (h,k).Here y=x^2-6x+8= (x-3)^2-9+8=(x-3)^2-1 :.Vertex is at (3, -1) we find y-intercept by putting x=0 in the equation. So y=0-0+8=8 and x-intercept by putting y=0 in the equation.
- 24/05/2011 · Best Answer: Hint: Using the x-intercepts and y = ax² + bx + c, find the quadratic formula. Remember that x-intercepts are the roots of the function, so... Remember that x-intercepts are the roots of the function, so...
- 0=x^2+8x+8 ___ is not factorable ___ use the quadratic formula to find the roots (x-intercepts) the vertex is on the axis of symmetry the equation for the axis of symmetry is x=-b/(2a)